1989 NCAA Division I Men's Ice Hockey Tournament

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1989 NCAA Division I Men's
Ice Hockey Tournament
Season 1988–89
Teams 12
Finals Site St. Paul Civic Center
St. Paul , Minnesota
Champions Harvard (1st title, 3rd title game,
11th Frozen Four)
Runner-Up Minnesota (9th title game,
14th Frozen Four)
Semifinalists Michigan State (7th Frozen Four)
Maine (2nd Frozen Four)
Winning Coach Bill Cleary (1st title)
MOP Ted Donato (Harvard)
Attendance 61,418
NCAA Division I Men's Ice Hockey Tournaments
← 1988  1990 →

The 1989 NCAA Men's Division I Ice Hockey Tournament was the culmination of the 1988–89 season in men's ice hockey for teams in Division I of the National Collegiate Athletic Association (NCAA). Beginning with the 1989 tournament, the first and quarterfinal rounds were changed to a best-of-three format from the previous two game, total goals series in place since 1981. Series were held at the campus of the higher seed. Semifinals and championship game remain single elimination.[1]

The Harvard Crimson defeated the Minnesota Golden Gophers in the championship game, held in St. Paul, Minnesota on April 1.

Tournament Bracket

  First Round
March 17–19
Quarterfinals
March 17–19
Semifinals
March 30–31
Championship Game
April 1
                                             
  1  Maine 6 3 4* 1  Maine 4  
4  Northern Michigan 9 2 0 5  Providence 8 2 3 2  Minnesota 7  
5  Providence 5 4 2
  2  Minnesota 4 4  
3  St. Lawrence 1 2   6  Wisconsin 2 2       2  Minnesota 3
6  Wisconsin 3 4     2  Harvard 4*
  2  Harvard 4 5  
3  Lake Superior State 6 4   3  Lake Superior State 2 2  
6  St. Cloud State 3 2   Third Place Game
  1  Michigan State 3 7 5* 2  Harvard 6
4  Boston College 8 4   4  Boston College 6 2 4 1  Michigan State 3   1  Maine 4
5  Bowling Green 5 2   1  Michigan State 7

* denotes overtime

All-Tournament Team[2]

* Most Outstanding Player(s)[3]

References

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External links

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