United States presidential election in Arizona, 1928

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United States presidential election in Arizona, 1928
← 1924 November 6, 1928[1] 1932 →
All 3 Arizona votes to the Electoral College
  Herbert Hoover - NARA - 532049.tif AlfredSmith.png
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 3 0
Popular vote 52,533 38,537
Percentage 57.57% 42.23%
President before election

Calvin Coolidge
Republican

 Elected President

Herbert Hoover
Republican

The 1928 United States presidential election in Arizona took place on November 6, 1928, as part of the 1928 United States presidential election. Arizona voters chose three representatives, or electors, to the Electoral College, who voted for President and Vice President.

Arizona was won by U.S. Secretary of Commerce Herbert Hoover (R–California), running with U.S. Senator from Kansas Charles Curtis, with 57.57% of the popular vote, against Governor of New York Al Smith (D–New York), running with U.S. Senator from Arkansas Joseph Taylor Robinson, with 42.23% of the popular vote.[2][3]

Results

United States presidential election in Arizona, 1928
Party Candidate Votes %
Republican Herbert Hoover 52,533 57.57%
Democratic Al Smith 38,537 42.23%
Communist William Z. Foster 184 0.20%
Total votes 91,254 100%

References

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