United States presidential election in Connecticut, 1836

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Main article: United States presidential election, 1836
United States presidential election in Connecticut, 1836
← 1832 November 3 – December 7, 1836 1840 →
  MartinVanBuren.png WHenryHarrison.png
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard Johnson Francis Granger
Electoral vote 8 0
Popular vote 19,294 18,799
Percentage 50.65% 49.35%

Lua error in package.lua at line 80: module 'strict' not found. The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a margin of 1.3%.

Results

United States presidential election in Connecticut, 1836[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren 19,294 50.65% 8
Whig William Henry Harrison 18,799 49.35% 0
Totals 38,093 100.0% 8

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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