United States presidential election in Indiana, 1996

Main article: United States presidential election, 1996

United States presidential election in Indiana, 1996

November 5, 1996

Nominee Bob Dole Bill Clinton Ross Perot Party Republican Democratic Reform Home state Kansas Arkansas Texas Running mate Jack Kemp Al Gore Patrick Choate Electoral vote 12 0 0 Popular vote 1,006,693 887,424 224,299 Percentage 47.13% 41.55% 10.50%

290px County Results   Clinton—80-90%   Clinton—70-80%   Clinton—60-70%   Clinton—50-60%   Dole—50-60%   Dole—60-70%   Dole—80-90%

President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

The 1996 United States presidential election in Indiana took place on November 5, 1996 throughout all 50 states and D.C.. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana was won by Senator Bob Dole (R-KS). The presidential contest in Indiana was not a surprise, with Dole winning 47.13% to 41.55% over President Bill Clinton (D) by a margin of 5.58%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with a significant 10.50% of the popular vote in Indiana. Indiana would stay a Republican state until 2008, in which Barack Obama won by a close margin, the first Democratic victory in Indiana since 1964.

Results

United States presidential election in Indiana, 1996
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Republican	Bob Dole	Jack Kemp	1,006,693	47.13%	12
	Democratic	Bill Clinton	Al Gore	887,424	41.55%	0
	Reform	Ross Perot	Patrick Choate	224,299	10.50%	0
	Libertarian	Harry Browne	Jo Jorgensen	15,632	0.73%	0
Totals				2,135,842	100.00%	12