United States presidential election in Iowa, 1912

United States presidential election in Iowa, 1912

November 5, 1912

Nominee Woodrow Wilson Theodore Roosevelt Party Democratic Progressive Home state New Jersey New York Running mate Thomas R. Marshall Hiram Johnson Electoral vote 13 0 Popular vote 185,325 161,819 Percentage 39.30% 32.87%   150px Nominee William Howard Taft Party Republican Home state Ohio Running mate Nicholas M. Butler (replacing James S. Sherman) Electoral vote 0 Popular vote 119,805 Percentage 24.33%

President before election William Howard Taft Republican Elected President Woodrow Wilson Democratic

Main article: United States presidential election, 1912

The 1912 United States presidential election in Iowa took place on November 5, 1912, as part of the 1912 United States presidential election. Iowa voters chose thirteen representatives, or electors, to the Electoral College, who voted for President and Vice President.

Iowa was won by Princeton University President Woodrow Wilson (D–Virginia), running with governor of Indiana Thomas R. Marshall, with 37.64% of the popular vote, against the 26th President of the United States Theodore Roosevelt (P–New York), running with governor of California Hiram Johnson, with 32.87% of the popular vote and the 27th President of the United States William Howard Taft (R–Ohio), running with Columbia University President Nicholas Murray Butler, with 24.33% of the popular vote.

Results

United States presidential election in Iowa, 1912
Party		Candidate	Votes	%
	Democratic	Woodrow Wilson	185,325	37.64%
	Progressive	Theodore Roosevelt	161,819	32.87%
	Republican	William Howard Taft	119,805	24.33%
	Socialist	Eugene V. Debs	16,967	3.45%
	Prohibition	Stuart Hamblen	8,440	1.71%
Total votes			492,356	100%