United States presidential election in Iowa, 1956

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United States presidential election in Iowa, 1956
← 1952 November 6, 1956[1] 1960 →
All 10 Iowa votes to the Electoral College
  President Eisenhower Portrait 1959.tif AdlaiEStevenson1900-1965.jpg
Nominee Dwight D. Eisenhower Adlai Stevenson
Party Republican Democratic
Home state Kansas Iowa
Running mate Richard Nixon Estes Kefauver
Electoral vote 10 0
Popular vote 729,187 501,858
Percentage 59.1% 40.7%
President before election

Dwight D. Eisenhower
Republican

 Elected President

Dwight D. Eisenhower
Republican

The 1956 United States presidential election in Iowa took place on November 6, 1956, as part of the 1956 United States presidential election. Iowa voters chose ten[2] representatives, or electors, to the Electoral College, who voted for President and Vice President.

Iowa was won by incumbent President Dwight D. Eisenhower (R–Kansas), running with Vice President Richard Nixon, with 59.06% of the popular vote, against Adlai Stevenson (D–Iowa), running with Senator Estes Kefauver, with 40.65% of the popular vote.[3][4]

Results

United States presidential election in Iowa, 1956
Party Candidate Votes %
Republican Dwight D. Eisenhower (inc.) 729,187 59.06%
Democratic Adlai Stevenson 501,858 40.65%
A.C.P. of Iowa T. Coleman Andrews 3,202 0.26%
Write-in 317 0.03%
Total votes 1,234,564 100%

References

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