United States presidential election in New Mexico, 1988

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United States presidential election in New Mexico, 1988

← 1984 November 8, 1988 1992 →
  150px Dukakis1988rally cropped.jpg
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 5 0
Popular vote 270,341 244,497
Percentage 51.86% 46.90%

350px
County Results
  Dukakis—70-80%
  Dukakis—60-70%
  Dukakis—50-60%
  Bush—<50%
  Bush—50-60%
  Bush—60-70%

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican

The 1988 United States presidential election in New Mexico took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. New Mexico voters chose 5 electors to the Electoral College, which selected the President and Vice President.

New Mexico was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.

New Mexico weighed in for this election as 2% more Democratic than the national average.

Partisan background

Bush's largely socially conservative rhetoric garnered him much support among social-conservatives nationwide. Seen here at campaign rally in Omaha, Nebraska.

The presidential election of 1988 was a very partisan election for New Mexico, with 98% of the electorate voting for either the Democratic or Republican parties.[1] This is one of the last Presidential elections in New Mexico in which you see the highly populated counties of Bernalillo and Los Alamos turning out primarily Republican. The Democratic stronghold in the northern part of the state is evident during this election, and remains largely intact from this point onward to current political times.

Republican victory

Bush won the election in New Mexico with a solid 5 point margin. The election results in New Mexico are reflective of a nationwide reconsolidation of base for the Republican Party, which took place through the 1980s. Through the passage of some very controversial economic programs, spearheaded by then President Ronald Reagan (called, collectively, "Reaganomics"), the mid-to-late 1980's saw a period of economic growth and stability. The hallmark for Reaganomics was, in part, the wide-scale deregulation of corporate interests, and tax cuts for the wealthy.[2]

Dukakis ran on a socially liberal agenda, and advocated for economic reform and governmental transparency. Bush, on the other hand, ran on a campaign of continuing the social and economic policies of former President Reagan - which gained him much support with social conservatives and people living in rural areas, who largely associated the Republican Party with the economic growth of the 1980s. Additionally, while the economic programs passed under Reagan, and furthered under Bush and Clinton, may have boosted the economy for a brief period, they are criticized by many analysts as "setting the stage" for economic troubles in the United State after 2007, such as the Great Recession.[3]

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Results

United States presidential election in New Mexico, 1988
Party Candidate Votes Percentage Electoral votes
Republican George H. W. Bush 270,341 51.86% 5
Democratic Michael Dukakis 244,497 46.90% 0
Libertarian Ron Paul 3,268 0.63% 0
New Alliance Party Lenora Fulani 2,237 0.43% 0
Socialist Workers Party James Warren 344 0.07% 0
Workers World Larry Holmes 258 0.05% 0
Prohibition Earl Dodge 249 0.05% 0
Write-Ins 93 0.02% 0
Totals 521,287 100.0% 5

See also

References

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