United States presidential election in Pennsylvania, 1948
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200px County results
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Lua error in package.lua at line 80: module 'strict' not found. The 1948 United States presidential election in Pennsylvania took place on November 2, 1948 throughout the continuous 48 states. Voters chose 35 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania voted for the Republican nominee, New York Governor Thomas E. Dewey, over the Democratic nominee, President Harry Truman. Dewey won Pennsylvania by a margin of 4.01%. As of 2012, this is the last time that a Democrat won the national election without carrying Pennsylvania. It was also the last time until 1968 that a presidential candidate won the election without carrying the state.
Results
| United States presidential [1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | Thomas E. Dewey | 1,902,197 | 50.93% | 35 | |
| Democratic | Harry Truman | 1,752,426 | 46.92% | 0 | |
| Progressive | Henry Wallace | 55,161 | 1.48% | 0 | |
| Socialist | Norman Thomas | 11,325 | 0.30% | 0 | |
| Prohibition | Claude Watson | 10,338 | 0.28% | 0 | |
| Militant Workers | Farrell Dobbs | 2,133 | 0.06% | 0 | |
| Industrial Government | Edward Teichert | 1,461 | 0.04% | 0 | |
| Write-ins | Write-ins | 107 | 0.00% | 0 | |
