United States presidential election in Wyoming, 1904

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United States presidential election in Wyoming, 1904

← 1900 November 8, 1904 1908 →
  150x150px AltonBParker.png
Nominee Theodore Roosevelt Alton Parker
Party Republican Democratic
Home state New York New York
Running mate Charles W. Fairbanks Henry Gassaway Davis
Electoral vote 3 0
Popular vote 20,846 8,930
Percentage 66.72% 29.08%

President before election

Theodore Roosevelt
Republican

Elected President

Theodore Roosevelt
Republican

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The 1904 United States presidential election in Wyoming took place on November 8, 1904, as part of the 1904 United States presidential election. Wyoming voters chose three representatives, or electors, to the Electoral College, who voted for President and Vice President.

Wyoming was won by the Secretary of War Theodore Roosevelt (RNew York), running with the 26th Vice President Charles W. Fairbanks, with 66.72% of the popular vote, against Chief Judge of the New York Court of Appeals Alton Parker (DNew York), running with Senator Henry Gassaway Davis, with 29.08% of the popular vote[1].

Results

United States presidential election in Wyoming, 1904[2]
Party Candidate Votes %
Republican Theodore Roosevelt 20,846 66.72%
Democratic William Jennings Bryan 8,930 29.08%
Socialist Eugene V. Debs 1,072 3.49%
Prohibition Silas Swallow 271 0.71%
Total votes 30,708 100%

References

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