1960 United States presidential election in Louisiana
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200px Parish Results
Kennedy—80-90%
Kennedy—70-80%
Kennedy—60-70%
Kennedy—50-60%
Kennedy—40-50%
Kennedy—<40%
Nixon—<40%
Nixon—40-50%
Nixon—50-60%
Unpledged—<40%
Unpledged—40-50%
Unpledged—50-60%
Unpledged—60-70%
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Lua error in package.lua at line 80: module 'strict' not found. The 1960 United States presidential election in Louisiana took place on November 8, 1960, as part of the 1960 United States presidential election. Louisiana voters chose ten[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Louisiana was won by Senator John F. Kennedy (D–Massachusetts), running with Senator Lyndon B. Johnson, with 50.42% of the popular vote against incumbent Vice President Richard Nixon (R–California), running with United States Ambassador to the United Nations Henry Cabot Lodge, Jr., with 28.59% of the popular vote.[3][4]
Louisiana has a higher Roman Catholic population in contrast to the rest of Southern United States, greatly benefiting Kennedy, the second Roman Catholic to head a major party ticket and the first elected to the presidency. This Catholic base was mostly concentrated in the southern half of the state, while Nixon carried the northern Protestant counties. As of the 2016 presidential election[update], this is the last election in which Jefferson Parish and St. Tammany Parish voted for the Democratic candidate.
Results
United States presidential election in Louisiana, 1960 | ||||
---|---|---|---|---|
Party | Candidate | Votes | % | |
Democratic | John F. Kennedy | 407,339 | 50.42% | |
Republican | Richard Nixon | 230,980 | 28.59% | |
States' Rights | Unpledged electors | 169,572 | 20.99% | |
Total votes | 807,891 | 100% |