1998 Prague Open – Doubles

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Doubles
1998 Prague Open
Champions Australia Wayne Arthurs
Australia Andrew Kratzmann[1]
Runners-up Sweden Fredrik Bergh
Sweden Nicklas Kulti
Final score 6–1, 6–1
Events
Singles men women
Doubles men women

The 1998 Prague Open was a men's tennis tournament played on Clay in Prague, Czech Republic that was part of the International Series of the 1998 ATP Tour. It was the twelfth edition of the tournament and was held from 27 April – 3 May 1998.

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

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2

Draw

Key

Finals

First Round Quarterfinals Semifinals Final[1]
1 Argentina L Lobo
Argentina D Orsanic
7 6
Czech Republic C Suk
Czech Republic B Ulihrach
6 4 1 Argentina L Lobo
Argentina D Orsanic
6 6
Russia A Cherkasov
Russia Y Kafelnikov
6 6 Russia A Cherkasov
Russia Y Kafelnikov
2 4
United States D Bowen
Finland T Ketola
2 2 1 Argentina L Lobo
Argentina D Orsanic
1 6 6
Australia Australia W Arthurs
Australia A Kratzmann
6 7 Australia W Arthurs
Australia A Kratzmann
6 3 7
3 Germany M-K Goellner
Germany D Prinosil
2 6 Australia W Arthurs
Australia A Kratzmann
6 6
Czech Republic P Luxa
Czech Republic D Škoch
6 5 7 Czech Republic P Luxa
Czech Republic D Škoch
3 4
Brazil F Meligeni
Brazil A Sá
4 7 5 Australia W Arthurs
Australia A Kratzmann
6 6
Argentina M Hood
Argentina S Prieto
6 7 Sweden F Bergh
Sweden N Kulti
1 1
Czech Republic C Doseděl
Slovakia K Kučera
2 6 Argentina M Hood
Argentina S Prieto
7 7
Australia P Kilderry
Ecuador N Lapentti
6 6 Australia P Kilderry
Ecuador N Lapentti
6 5
4 Mexico D Roditi
Netherlands F Wibier
2 3 Argentina M Hood
Argentina S Prieto
6 6 3
South Africa M Ondruska
United States J Tarango
6 6 6 Sweden F Bergh
Sweden N Kulti
7 4 6
Czech Republic P Pála
Czech Republic R Štěpánek
7 0 4 South Africa M Ondruska
United States J Tarango
3 3
Sweden F Bergh
Sweden N Kulti
6 6 Sweden F Bergh
Sweden N Kulti
6 6
2 Czech Republic J Novák
Czech Republic P Vízner
3 3

References

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