File:Position and momentum of a Gaussian initial state for a QHO, narrow.gif

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Position_and_momentum_of_a_Gaussian_initial_state_for_a_QHO,_narrow.gif(360 × 223 pixels, file size: 255 KB, MIME type: image/gif, looped, 63 frames)

Summary

Description

made with Mathematica using the following commands: probX[x_, t_, m_, h_, om1_, om2_, x0_] =

Sqrt[m om1 om2^2 /(Pi h (om1^2 Sin[om2 t]^2 + om2^2 Cos[om2 t]^2))]*
 Exp[-(m om1 om2^2 / h)*(x - x0*Cos[om2 t])^2/(om1^2 Sin[om2 t]^2 + 
      om2^2 Cos[om2 t]^2)]

probP[p_, t_, m_, h_, om1_, om2_, x0_] =

Sqrt[om1/(Pi m h (om1^2 Cos[om2 t]^2 + om2^2 Sin[om2 t]^2))]*
 Exp[-(om1/ (m h))*(p + m om1 x0*Sin[om2 t])^2/(om1^2 Cos[om2 t]^2 + 
      om2^2 Sin[om2 t]^2)]

v[x_, m_, om2_] = m om2^2 x^2/2 frame2[t_] :=

Plot[{probX[x, t, 1, 1, 2, 1, -10], probP[x, t, 1, 1, 2, 1, -10], 
  v[x, 1/200, 1]}, {x, -25, 25}, Axes -> {True, False}, 
 Ticks -> None, PlotRange -> {0, 1.2}]

frames2 = ParallelTable[frame2[t], {t, 0, 2*Pi, 0.1}];

Source

made with Mathematica

Date

2012-05-20

Author

Teply

Permission
(Reusing this file)

See below.


Licensing

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File history

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Date/TimeThumbnailDimensionsUserComment
current17:44, 25 April 2021Thumbnail for version as of 17:44, 25 April 2021360 × 223 (255 KB)Thales (talk | contribs)
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