File:Pythagorean Theorem derived using Conant-Beyer Projection Generalization.gif
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Pythagorean_Theorem_derived_using_Conant-Beyer_Projection_Generalization.gif (334 × 357 pixels, file size: 96 KB, MIME type: image/gif, looped, 28 frames, 4.0 s)
Summary
The Pythagorean theorem shown using the Conant-Beyer Generalization by projecting a line segment (shown in blue) onto the x-axis and the y-axis. The sum of the squares of the projection lengths (shown in green) equals the square of the length of the original line (a2 + b2 = c2). Bringing the original line and its projections together forms a right triangle.
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 14:11, 9 January 2017 | | 334 × 357 (96 KB) | 127.0.0.1 (talk) | The Pythagorean theorem shown using the Conant-Beyer Generalization by projecting a line segment (shown in blue) onto the <i>x</i>-axis and the <i>y</i>-axis. The sum of the squares of the projection lengths (shown in green) equals the square of the length of the original line (<i>a</i><sup>2</sup> + <i>b</i><sup>2</sup> = <i>c</i><sup>2</sup>). Bringing the original line and its projections together forms a right triangle. |
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