United States elections, 1884
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| President | Republican | Democratic |
| House | Democratic | Democratic |
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The 1884 United States general election was held on November 4, electing the members of the 49th United States Congress. The election took place during the Third Party System.
In the Presidential election, Democratic Governor Grover Cleveland of New York defeated Republican former Secretary of State James G. Blaine.[1] Though Cleveland won the popular vote by less than 1%, he won by a fairly comfortable margin in the electoral college. Cleveland won the South and the critical state of New York, while Blaine took most of the rest of the country. This was the most recent example of an incumbent President being denied re-nomination by his party, as Blaine defeated one-term incumbent President Chester A. Arthur at the 1884 Republican National Convention. Cleveland took the Democratic nomination on the second ballot of the 1884 Democratic National Convention, defeating Delaware Senator Thomas F. Bayard and several other candidates. Cleveland's win made him the first Democratic President to win election since the 1856 election.
Republicans picked up several seats in the House, but Democrats continued to command a majority in the chamber.[2]
In the Senate, Republicans made moderate gains and established a clear majority.[3]
See also
- United States presidential election, 1884
- United States House of Representatives elections, 1884
- United States Senate elections, 1884
References
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