United States elections, 1894
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| President | Democratic | Democratic |
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The 1894 United States general election was held on November 6, and elected the members of the 54th United States Congress. These were mid-term elections during Democratic President Grover Cleveland's second term. During the 54th Congress, Utah was admitted to the union. The election was the last election of the Third Party System and set the stage for the Fourth Party System.
As the second occurrence of the six-year itch, the Democrats suffered a landslide defeat in the House and lost over 100 seats to the Republicans[1] in the single largest swing in the history of the House. The Democrats also lost four seats in the Senate,[2] thus resulting in the President's party completely losing control of both houses of Congress, the first time this ever happened in a midterm election.
The Democratic Party losses can be traced largely to the Panic of 1893 and the ineffective party leadership of Cleveland. Republicans effectively used the issues of the tariff, bimetallism, and the Cuban War of Independence against Cleveland. The Democrats suffered huge defeats outside of the South (almost ninety percent of Northeastern and Midwestern House Democrats lost re-election), and the Democratic Party underwent a major turnover in party leadership. With the defeat of many Bourbon Democrats, William Jennings Bryan took the party in a more populist direction starting with the 1896 elections.[3]
Contents
Federal
States
See also
- United States presidential election, 1892
- United States House of Representatives elections, 1892
- United States Senate elections, 1892
References
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