United States presidential election in Alabama, 1836

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Main article: United States presidential election, 1836
United States presidential election in Alabama, 1836
← 1832 November 3 – December 7, 1836 1840 →
  MartinVanBuren.png HLWhite.jpg
Nominee Martin Van Buren Hugh White
Party Democratic Whig
Home state New York Tennessee
Running mate Richard Johnson John Tyler
Electoral vote 7 0
Popular vote 20,638 16,658
Percentage 55.34% 44.66%
President before election

Andrew Jackson
Democratic

 Elected President

Martin Van Buren
Democratic

Lua error in package.lua at line 80: module 'strict' not found. The 1836 United States presidential election in Alabama took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Alabama voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Alabama by a margin of 10.68%.

Results

United States presidential election in Alabama, 1836[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren 20,638 55.34% 7
Whig Hugh White 16,658 44.66% 0
Totals 37,296 100.0% 7

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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