United States presidential election in Arkansas, 1836

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Main article: United States presidential election, 1836
United States presidential election in Arkansas, 1836
← 1832 November 3 – December 7, 1836 1840 →
  MartinVanBuren.png HLWhite.jpg
Nominee Martin Van Buren Hugh White
Party Democratic Whig
Home state New York Tennessee
Running mate Richard Johnson John Tyler
Electoral vote 3 0
Popular vote 2,380 1,334
Percentage 64.08% 35.92%
President before election

Andrew Jackson
Democratic

 Elected President

Martin Van Buren
Democratic
Elections in Arkansas
Seal of Arkansas.svg
This box:

The 1836 United States presidential election in Arkansas took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Arkansas voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Arkansas by a margin of 28.16%.

Results

United States presidential election in Arkansas, 1836[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren 2,380 64.08% 3
Whig Hugh White 1,334 35.92% 0
Totals 3,714 100.0% 3

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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