United States presidential election in Connecticut, 1884

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Main article: United States presidential election, 1884
United States presidential election in Connecticut, 1884
← 1880 November 4, 1884 1888 →
  StephenGroverCleveland.png JamesGBlaine.png
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 6 0
Popular vote 67,182 65,898
Percentage 48.95% 48.01%
President before election

Chester A. Arthur
Republican

 Elected President

Grover Cleveland
Democratic

Lua error in package.lua at line 80: module 'strict' not found. The 1884 United States presidential election in Connecticut took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won the state by a very narrow margin of 0.94%.

Results

United States presidential election in Connecticut, 1884[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 67,182 48.95% 6 100.00%
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 65,898 48.01% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 2,493 1.82% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 1,684 1.23% 0 0.00%
Total 137,257 100.00% 6 100.00%

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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