United States presidential election in Connecticut, 1992

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United States presidential election in Connecticut, 1992

← 1988 November 3, 1992 1996 →
  44 Bill Clinton 3x4.jpg 43 George H.W. Bush 3x4.jpg RossPerotColor.jpg
Nominee Bill Clinton George H.W. Bush Ross Perot
Party Democratic Republican Independent
Home state Arkansas Texas Texas
Running mate Al Gore Dan Quayle James Stockdale
Electoral vote 8 0 0
Popular vote 682,318 578,313 348,771
Percentage 42.21% 35.78% 21.58%

Connecticut Presidential Election Results by County, 1992.svg
County Results
  Clinton—40-50%
  Bush—<40%
  Bush—40-50%

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

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The 1992 United States presidential election in Connecticut took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut was won by Governor Bill Clinton (D-Arkansas) with 42.21% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 35.78%. Businessman Ross Perot (I-Texas) finished in third with 21.58% of the popular vote. Clinton won Connecticut by a margin of 6.43%, ending the state's status as a swing state, as it has voted Democratic in every election since.[1] Clinton ultimately won the national vote, defeating incumbent President Bush.[2]

Results

United States presidential election in Connecticut, 1992[1]
Party Candidate Votes Percentage Electoral votes
Democratic Bill Clinton 682,318 42.21% 8
Republican George H.W. Bush (incumbent) 578,313 35.78% 0
Independent Ross Perot 348,771 21.58% 0
Libertarian Andre Marrou 5,391 0.33% 0
New Alliance Lenora Fulani 1,363 0.08% 0
N/A Other 176 0.01% 0
Totals 1,616,332 100.0% 8
Voter Turnout (Voting age/Registered) 64%/82%

References

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