United States presidential election in Delaware, 1828

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Main article: United States presidential election, 1828
United States presidential election in Delaware, 1828
← 1824 October 31 – December 2, 1828 1832 →
  JohnQAdams.png Andrew Jackson.jpg
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote 3 0
Elections in Delaware
Seal of Delaware.svg
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The 1828 United States presidential election in Delaware took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware cast three electoral votes for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote.[1]

Results

United States presidential election in Delaware, 1828[2]
Party Candidate Votes Percentage Electoral votes
National Republican John Quincy Adams – – 3
Democratic Andrew Jackson – – 0
Totals – – 3

References

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