United States presidential election in Idaho, 1944

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United States presidential election in Idaho, 1944
← 1940 November 7, 1944[1] 1948 →
All 4 Idaho votes to the Electoral College
  1944 portrait of FDR (1)(small).jpg ThomasDewey.png
Nominee Franklin D. Roosevelt Thomas E. Dewey
Party Democratic Republican
Home state New York New York
Running mate Harry S. Truman John W. Bricker
Electoral vote 4 0
Popular vote 107,399 100,137
Percentage 51.6% 48.1%
President before election

Franklin D. Roosevelt
Democratic

 Elected President

Franklin D. Roosevelt
Democratic

The 1944 United States presidential election in Idaho took place on November 7, 1944, as part of the 1944 United States presidential election. Idaho voters chose four[2] representatives, or electors, to the Electoral College, who voted for President and Vice President.

Idaho was won by incumbent President Franklin D. Roosevelt (D–New York), running with Senator Harry S. Truman, with 51.55% of the popular vote, against Governor Thomas E. Dewey (R–New York), running with Governor John W. Bricker, with 48.07% of the popular vote.[3][4]

Results

United States presidential election in Idaho, 1944
Party Candidate Votes %
Democratic Franklin D. Roosevelt (inc.) 107,399 51.55%
Republican Thomas E. Dewey 100,137 48.07%
Write-in 785 0.38%
Total votes 208,321 100%

References

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