United States presidential election in Kansas, 1948
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All 8 Kansas votes to the Electoral College |
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The 1948 United States presidential election in Kansas took place on November 2, 1948, as part of the 1948 United States presidential election. Kansas voters chose eight[2] representatives, or electors, to the Electoral College, who voted for President and Vice President.
Kansas was won by Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 53.63% of the popular vote, against incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 44.61% of the popular vote.[3][4]
Results
United States presidential election in Kansas, 1948 | ||||
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Party | Candidate | Votes | % | |
Republican | Thomas Dewey | 423,039 | 53.63% | |
Democratic | Harry S. Truman (inc.) | 351,902 | 44.61% | |
Prohibition | Claude A. Watson | 6,468 | 0.82% | |
Progressive | Henry A. Wallace | 4,603 | 0.58% | |
Socialist | Norman Thomas | 2,807 | 0.38% | |
Total votes | 788,819 | 100% |
References
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