United States presidential election in Kansas, 1948

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United States presidential election in Kansas, 1948

← 1944 November 2, 1948[1] 1952 →

All 8 Kansas votes to the Electoral College
  ThomasDewey.png Harry S. Truman.jpg
Nominee Thomas Dewey Harry S. Truman
Party Republican Democratic
Home state New York Missouri
Running mate Earl Warren Alben W. Barkley
Electoral vote 8 0
Popular vote 423,039 351,902
Percentage 53.6% 44.6%

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Kansas took place on November 2, 1948, as part of the 1948 United States presidential election. Kansas voters chose eight[2] representatives, or electors, to the Electoral College, who voted for President and Vice President.

Kansas was won by Governor Thomas Dewey (RNew York), running with Governor Earl Warren, with 53.63% of the popular vote, against incumbent President Harry S. Truman (DMissouri), running with Senator Alben W. Barkley, with 44.61% of the popular vote.[3][4]

Results

United States presidential election in Kansas, 1948
Party Candidate Votes %
Republican Thomas Dewey 423,039 53.63%
Democratic Harry S. Truman (inc.) 351,902 44.61%
Prohibition Claude A. Watson 6,468 0.82%
Progressive Henry A. Wallace 4,603 0.58%
Socialist Norman Thomas 2,807 0.38%
Total votes 788,819 100%

References

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