United States presidential election in Maine, 1888

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United States presidential election in Maine, 1888

← 1884 November 6, 1888 1892 →
  Pach Brothers - Benjamin Harrison.jpg StephenGroverCleveland.png
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote 6 0
Popular vote 73,730 50,472
Percentage 57.49% 39.35%

President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Maine took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Maine voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a margin of 18.14%.

Results

United States presidential election in Maine, 1888[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 73,730 57.49% 6 100.00%
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 50,472 39.35% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 2,691 2.10% 0 0.00%
style="background-color: Template:Labor Party (United States, 19th century)/meta/color; width: 5px;" | Labor Alson Streeter of Illinois Charles E. Cunningham of Arkansas 1,344 1.05% 0 0.00%
N/A Others Others 16 0.01% 0 0.00%
Total 128,253 100.00% 6 100.00%

References

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