United States presidential election in Oregon, 1992

Main article: United States presidential election, 1992

United States presidential election in Oregon, 1992

November 3, 1992

Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle James Stockdale Electoral vote 7 0 0 Popular vote 621,314 475,757 354,091 Percentage 42.48% 32.53% 24.21%

375px County Results   Clinton—50-60%   Clinton—40-50%   Clinton—<40%   Bush—<40%   Bush—40-50%   Bush—50-60%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in Oregon took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Oregon was won by Governor Bill Clinton (D-Arkansas) with 42.48% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 32.53%. Businessman Ross Perot (I-Texas) finished in third with 24.21% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.

Results

United States presidential election in Oregon, 1992
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton	621,314	42.48%	7
	Republican	George H.W. Bush (incumbent)	475,757	32.53%	0
	Independent	Ross Perot	354,091	24.21%	0
	Libertarian	Andre Marrou	4,277	0.29%	0
	New Alliance	Lenora Fulani	3,030	0.21%	0
	Other write-ins		2,609	0.18%	0
	America First	James "Bo" Gritz (write-in)	1,470	0.10%	0
	Natural Law	Dr. John Hagelin (write-in)	91	0.01%	0
	Socialist	J. Quinn Brisben (write-in)	4	0.00%	0
Totals			1,462,643	100.0%	7