United States presidential election in Pennsylvania, 1840

From Infogalactic: the planetary knowledge core
Jump to: navigation, search

<templatestyles src="Module:Hatnote/styles.css"></templatestyles>

Main article: United States presidential election, 1840
United States presidential election in Pennsylvania, 1840
← 1836 October 30 – December 2, 1840 1844 →
  WHenryHarrison.png MartinVanBuren.png
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 30 0
Popular vote 144,010 143,676
Percentage 50.00% 49.88%
President before election

Martin Van Buren
Democratic

 Elected President

William Henry Harrison
Whig

Lua error in package.lua at line 80: module 'strict' not found. The 1840 United States presidential election in Pennsylvania took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Whig candidate, William Henry Harrison, over the Democratic candidate, Martin Van Buren. Harrison won Pennsylvania by a margin of 0.12%.

Results

United States presidential election in Pennsylvania, 1840[1]
Party Candidate Votes Percentage Electoral votes
Whig William Henry Harrison 144,010 50.00% 30
Democratic Martin Van Buren 143,676 49.88% 0
Liberty James G. Birney 340 0.12% 0
Totals 288,026 100.0% 30

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
Retrieved from "https://infogalactic.com/w/index.php?title=United_States_presidential_election_in_Pennsylvania,_1840&oldid=707449702"