United States presidential election in Pennsylvania, 1884

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Main article: United States presidential election, 1884
United States presidential election in Pennsylvania, 1884
← 1880 November 4, 1884 1888 →
  JamesGBlaine.png StephenGroverCleveland.png
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 30 0
Popular vote 478,804 392,785
Percentage 52.97% 43.46%
President before election

Chester A. Arthur
Republican

 Elected President

Grover Cleveland
Democratic

Lua error in package.lua at line 80: module 'strict' not found. The 1884 United States presidential election in Pennsylvania took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won Pennsylvania by a margin of 9.51%.

Results

United States presidential election in Pennsylvania, 1884[1]
Party Candidate Votes Percentage Electoral votes
Republican James G. Blaine 478,804 52.97% 30
Democratic Grover Cleveland 392,785 43.46% 0
Greenback Labor Benjamin Butler 16,992 1.88% 0
Prohibition John St. John 15,283 1.69% 0
Totals 903,864 100.0% 30

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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