United States presidential election in Pennsylvania, 1892

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Main article: United States presidential election, 1892
United States presidential election in Pennsylvania, 1892
← 1888 November 8, 1892 1896 →
  Pach Brothers - Benjamin Harrison.jpg StephenGroverCleveland.png
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Whitelaw Reid Adlai Stevenson
Electoral vote 32 0
Popular vote 516,011 452,264
Percentage 51.45% 45.09%
President before election

Benjamin Harrison
Republican

 Elected President

Grover Cleveland
Democratic

Lua error in package.lua at line 80: module 'strict' not found. The 1892 United States presidential election in Pennsylvania took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose 32 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Republican nominee, incumbent President Benjamin Harrison, over the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term. Harrison won Pennsylvania by a margin of 6.36%.

Results

United States presidential election in Pennsylvania, 1892[1]
Party Candidate Votes Percentage Electoral votes
Republican Benjamin Harrison (incumbent) 516,011 51.45% 32
Democratic Grover Cleveland 452,264 45.09% 0
Prohibition John Bidwell 25,123 2.50% 0
People's James Weaver 8,714 0.87% 0
Socialist Labor Simon Wing 898 0.09% 0
Totals 1,003,010 100.0% 32

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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