United States presidential election in Maine, 1896

Main article: United States presidential election, 1896

United States presidential election in Maine, 1896

November 3, 1896

Nominee William McKinley William Jennings Bryan Party Republican Democratic Home state Ohio Nebraska Running mate Garret Hobart Arthur Sewall Electoral vote 6 0 Popular vote 80,403 34,587 Percentage 67.90% 29.21%

President before election Grover Cleveland Democratic Elected President William McKinley Republican

The 1896 United States presidential election in Maine took place on November 3, 1896. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Maine voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won the state by a margin of 38.69%.

Results

United States presidential election in Maine, 1896
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	William McKinley of Ohio	Garret Hobart of New Jersey	80,403	67.90%	6	100.00%
	Democratic	William Jennings Bryan of Nebraska	Arthur Sewall of Maine	34,587	29.21%	0	0.00%
style="background-color: Template:National Democratic Party (United States)/meta/color; width: 5px;" |	[[National Democratic Party (United States)|Template:National Democratic Party (United States)/meta/shortname]]	John McAuley Palmer of Illinois	Simon Bolivar Buckner of Kentucky	1,867	1.58%	0	0.00%
	Prohibition	Joshua Levering of Maryland	Hale Johnson of Illinois	1,562	1.32%	0	0.00%
Total				118,419	100.00%	6	100.00%